Phrases Differentiation Previous Year Question Paper and Solution with PDF

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Phrases Previous Year Questions (PYQs)

Phrases Differentiation PYQ

Qus : 1Phrases PYQ 2018

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Phrases Mathematics PYQPhrases Differentiation (Disha JEE) PYQ

Solution

Qus : 2Phrases PYQ 2022

The function

$f(x)=\begin{cases}{{(1+2x)}^{1/x}} & {,x\ne0} \\ {{e}^2} & {,x=0}\end{cases}$ , is

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Phrases Previous Year PYQPhrases NIMCET 2022 PYQ

Solution

Qus : 3Phrases PYQ 2022

$x^my^n$ =

$(x+y)^{m+n}$ , then

$\frac{dy}{dx}$ is

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Phrases Previous Year PYQPhrases NIMCET 2022 PYQ

Solution

Qus : 4Phrases PYQ 2021

$y={\tan }^{-1}\lgroup{\frac{3x-{x}^3}{1-3{x}^2}}\rgroup\, ,\, \frac{-1}{\sqrt[]{3}}{\lt}x{\lt}\frac{1}{\sqrt[]{3}}$ then

$\frac{dy}{dx}$ is

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Phrases Previous Year PYQPhrases NIMCET 2021 PYQ

Solution

Incorrect question

Qus : 5Phrases PYQ 2021

$y=\sin ^{-1}(\frac{{x}^2+1}{\sqrt[]{1+3{x}^2+{x}^4}}),\, (x>0),$ then

$\frac{dy}{dx}$ =

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Phrases Previous Year PYQPhrases NIMCET 2021 PYQ

Solution

Qus : 6Phrases PYQ 2018

Differential coefficient of

with respect to

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Phrases Previous Year PYQPhrases NIMCET 2018 PYQ

Solution

Qus : 7Phrases PYQ 2017

If y = cos²x², find dx/dy

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Phrases Previous Year PYQPhrases NIMCET 2017 PYQ

Solution

Let y = (cos x²)²

= 2 (cos x2) sin x2 .2x

= -4 (cos x2) sin x2

Qus : 8Phrases PYQ 2017

The derivative of (x³ + e^x + 3^x + cotx) with respect to x is

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Phrases Previous Year PYQPhrases NIMCET 2017 PYQ

Solution

Let y=x³+ e^x+ 3^x+ cotx

Now,

= 3x²+ e^x+ 3^x log3 - cosec² x

Qus : 9Phrases PYQ 2017

Differentiate [- log(log x), x > 1] with respect to x

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Phrases Previous Year PYQPhrases NIMCET 2017 PYQ

Solution

Let y = - log(log x), x>1

On differentiating both sides,

= -

(log (log x))

(log x)

Qus : 10Phrases PYQ 2015

With the usual notation

$\frac{d^{2}x}{dy^{2}}$

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Phrases Previous Year PYQPhrases NIMCET 2015 PYQ

Solution

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